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  1. #include <stdio.h>
  2. #include <math.h>
  3. int main(void) {
  4. 	int t, n, m, k;
  5. 	scanf("%d",&t);
  6. 	while(t--){
  7. 		scanf("%d%d",&n,&m);
  8. 		k = m/(float)n*100+1;
  9. 		if(k<100) printf("%d\n",(int)ceil((double)(100*m-k*n)/(k-100)));
  10. 		else printf("-1\n");
  11. 	}
  12. 	return 0;
  13. }
Success #stdin #stdout 0s 2252KB
comments (?)
stdin
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6
10 8
100 80
47 47
99000 0
1000000000 470000000
1000000000 0
stdout
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1
6
-1
1000
19230770
10101011
https://ideone.com/uumkuB
RATIO
language:
C (gcc 8.3)
created:
10 years ago
visibility:
secret

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