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  1. #include<iostream>
  2. #include<stdio.h>
  3. #include<string.h>
  4. using namespace std;
  5. char store[26][6]={"ka","zu","mi","te","ku","lu","ji","ri","ki","zu","me","ta","rin","to","mo","no","ke","shi","ari","chi","do","ru","mei","na","fu","zi"};
  6. int main()
  7. {
  8.  
  9. 	int test=10;
  10. 	while(test--)
  11. 	{
  12. 	char ch[50];
  13. 	gets(ch);
  14. 	int length=strlen(ch);
  15. 	for(int i=0;i<=length;i++)
  16. 	{
  17. 		if(ch[i]=='~'||ch[i]=='\0')
  18. 		{
  19. 			int j=i-1;
  20. 			for(;(j-1)!=-1&&(ch[j-1]!='\0');j--);
  21. 			ch[i]='\0';
  22. 			for(int k=0;k<26;k++)
  23. 			{
  24. 				char *c=ch;
  25. 				c=c+j;
  26. 				if(strcmp(c,store[k])==0 )
  27. 				{cout<<(char)(97+k);break;}
  28.  
  29. 			}
  30. 		}
  31. 	}
  32. 	cout<<endl;
  33. 	}
  34. 	return 0;
  35. }
  36.  
  37.  
Success #stdin #stdout 0s 2732KB
comments (?)
stdin
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chi~ri~ku
ka~to~ari~mei~ku~shi
chi~mo
chi~ri~ki~ari
no~shi~mo~zu~ta~ku~rin
ki~ari
ari~ki~na
te~ki~ru~ki~te~ku~te
zu~fu
ri~ka~ta~lu
stdout
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the
answer
to
this
problem
is
six
divided
by
half
https://ideone.com/8fPN8g
language:
C++ 4.3.2 (gcc-4.3.2)
created:
11 years ago
visibility:
public

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