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  1. def sum_dig_pow(a, b):
  2.     def _check_dig(dig):
  3.     	return dig == sum(int(a)**i for i,a in enumerate(str(dig), 1))
  4.  
  5.     return list(filter(_check_dig, range(a, b+1)))
  6.  
  7. print (sum_dig_pow(10, 100000))
  8.  
Success #stdin #stdout 0.31s 9252KB
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Standard input is empty
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[89, 135, 175, 518, 598, 1306, 1676, 2427]
https://ideone.com/7RBLrr
language:
Python 3 nbc (python 3.7.3)
created:
4 years ago
visibility:
public

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