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  1. //i;j;d;f(char*s,int n){for(i=0;i<n;i++)for(j=0;j+i<strlen(s);j=d+i+(n<2)){d=j-i+2*n-2;putchar(s[i+j]);if(i>0&i<n-1&d<strlen(s))putchar(s[d]);}}
  2. //t;i;j;d;f(s,n)char*s;{for(t=strlen(s),i=0;i<n;i++)for(j=0;j+i<t;j=d+i+(n<2))d=j-i+2*~-n,putchar(s[i+j]),i>0&i<n-1&d<t&&putchar(s[d]);}
  3.  
  4. // C variable and function declaration magic
  5. t;i;j;d;f(s,n)char*s;{
  6.         // Iterate through each "row" of the string
  7.         for(t=strlen(s),i=0;++i<n;)
  8.             // Iterate through each element on the row
  9.             // The original index iterator here was j+=2*(n-1), which is a full "zig-zag" forward
  10.             // The (n<2) is for the edge case of n==1, which will break the existing logic.
  11.             for(j=0; j+i<t; j=d+i+(n<2))
  12.                 // If j+i is the "zig", d is the "zag": Original index was d=j+i+2*(n-i-1)
  13.                 // Two's complement swag here courtesy of Jonathan Frech
  14.                 d=j-i+2*~-n,
  15.                 putchar(s[i+j]),
  16.                 // Short circuit logic to write the "zag" character if we're not on the first or last row
  17.                 i>0 & i<n-1 & d<t && putchar(s[d]);
  18.     }
  19.  
  20. main(){
  21. 	f("WATERMELON",3); putchar('\n');
  22. 	f("WATERMELON",4); putchar('\n');
  23. 	f("programmingpuzzles",5); putchar('\n');
  24. 	f("codegolf",3); putchar('\n');
  25. 	f("elephant",4); putchar('\n');
  26. 	f("1234567",3); putchar('\n');
  27. 	f("ABABABABAB",2); putchar('\n');
  28. 	f("qwertyuiop",1); putchar('\n');
  29.  
  30. }
Success #stdin #stdout 0s 9424KB
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stdin
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Standard input is empty
stdout
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AEMLNTE
AMLTROEN
rmnlsomgzgapzru
oeofdl
latehp
24637
BBBBB
https://ideone.com/yxer15
language:
C (gcc 8.3)
created:
5 years ago
visibility:
public

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