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  1. /*
  2. Scrieti un program care calculeaza suma a doua fractii. Cele doua fractii de insumat se introduc de la tastatura si rezultatul se
  3. va scrie ca o operatie de fractii ireductibile ca in exemplele de mai jos. Daca se introduce o valoare zero pentru numitor, atunc
  4. se va cere o alta valoare pana cand aceasta va fi nenula. Se va lucra cu numere naturale pozitive pentru numaratori si numitori din
  5. intervalul [1,80000];
  6.  
  7. Input:
  8. Introduceti cele doua fractii:
  9.  
  10. Fractie#1:
  11. Numaratorul = 2
  12. Numitorul = 3
  13. Fractie#2:
  14. Numaratorul = 9
  15. Numitorul = 19
  16. Fractie#suma:
  17. 2/3+1/2=7/6
  18.  
  19. */
  20. #include <stdio.h>
  21.  
  22. typedef struct Fraction {
  23.   int nr,
  24.       num;
  25. } TFraction;
  26.  
  27. int euclid(int a, int b) {
  28.   int r;
  29.   while(b){
  30.     r = a%b;
  31.     a = b;
  32.     b = r;
  33.   }
  34.   return a;
  35. }
  36.  
  37. void display(TFraction f){
  38.   printf("%d/%d\n",f.nr,f.num);
  39. }
  40.  
  41. void simplify(TFraction *p) {
  42.     int gcd = euclid(p->nr, p->num);
  43.     p->nr = p->nr/gcd;
  44.     p->num = p->num/gcd;
  45. }
  46.  
  47. void read(TFraction*p){
  48.   printf("Nr=");
  49.   scanf("%d",&p->nr);
  50.   printf("Num=");
  51.   while(scanf("%d",&p->num) && !p->num )
  52.         printf("The denominator must be !=0. Again!");
  53.   simplify(p);
  54. }
  55.  
  56. void sum(TFraction f1, TFraction f2, TFraction *p) {
  57.   p->nr = f1.nr * f2.num + f2.nr * f1.num;
  58.   p->num = f1.num * f2.num;
  59.   simplify(p);
  60. }
  61.  
  62. int main(int argc, char const *argv[]) {
  63.   TFraction F1,F2,FSum;
  64.   printf("Fraction#1:\n");
  65.   read(&F1);
  66.   display(F1);
  67.   printf("Fraction#2:\n");
  68.   read(&F2);
  69.   display(F2);
  70.   sum(F1,F2,&FSum);
  71.   printf("%s","Fraction#Sum = ");
  72.   display(FSum);
  73.   printf("%d/%d+%d/%d=%d/%d\n",F1.nr, F1.num, F2.nr, F2.num,FSum.nr, FSum.num);
  74.   return 0;
  75. }
  76.  
Success #stdin #stdout 0s 5396KB
comments (?)
stdin 
8
10
4
20
stdout 
Fraction#1:
Nr=Num=4/5
Fraction#2:
Nr=Num=1/5
Fraction#Sum = 1/1
4/5+1/5=1/1
https://ideone.com/UU3mPG
Sum of Two Fractions using pointers and struct
language:
C (gcc 8.3)
created:
1 year ago
visibility:
secret

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