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  1. from itertools import islice
  2.  
  3. linCirc  = [[1,10],
  4.             [2, 1],
  5.             [0, 2],
  6.             [2, 2],
  7.             [2, 3],
  8.             [2, 4],
  9.             [2, 0],
  10.             [2, 5]]
  11.  
  12. it = iter(linCirc)
  13. for element, n in it:
  14.     if not element: # skip n elements
  15.        next(islice(it, n, n), None) # see consume() recipe from itertools docs
  16.     print(element, n)
Success #stdin #stdout 0.02s 5852KB
comments (?)
stdin 
Standard input is empty
stdout 
1 10
2 1
0 2
2 4
2 0
2 5
https://ideone.com/T736t
language:
Python 3 (python  3.12)
created:
13 years ago
visibility:
secret

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