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  1. def f(a)
  2.   b = a.select(&:odd?).sort
  3.   c = a.select(&:even?).sort.reverse.map {|n| n / 2}
  4.   a.map {|n| n.odd? ? b.shift : c.shift}
  5. end
  6. p f [0, 9, 8, 4, 6, 5, 1, 2, 7, 3]
  7.  
Success #stdin #stdout 0.01s 6312KB
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[4, 1, 3, 2, 1, 3, 5, 0, 7, 9]
https://ideone.com/R93NWY
language:
Ruby (ruby 2.5.5)
created:
6 years ago
visibility:
secret

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