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  1. def f(n):
  2. 	a=[0];i=1
  3. 	while n:a+=[i-a[a[a[i-1]]]];i+=1;n-=1
  4. 	return a[i-1]
  5.  
  6. for i in list(range(21))+[10000]:
  7. 	print(i,f(i))
Success #stdin #stdout 0.04s 9984KB
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stdin
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Standard input is empty
stdout
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0 0
1 1
2 1
3 2
4 3
5 4
6 4
7 5
8 5
9 6
10 7
11 7
12 8
13 9
14 10
15 10
16 11
17 12
18 13
19 13
20 14
10000 6823
https://ideone.com/Q32qge
language:
Python 3 (python  3.9.5)
created:
7 years ago
visibility:
public

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