\begin{theorem} \label{tmn_0_0}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)}{\sin^{0}(4\theta) \sin^{0}(8\theta)},
\beta = \frac{\sin^{0}(4\theta)}{\sin^{0}(8\theta) \sin^{0}(2\theta)},
\gamma = \frac{\sin^{0}(8\theta)}{\sin^{0}(2\theta) \sin^{0}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_0}
x^3 - 3 x^2 + 3 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_0_0}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{0}
\end{equation}
\begin{equation} \label{gmn_0_0}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{0}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_0_3}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)\sin^{3}(8\theta)}{\sin^{3}(4\theta) },
\beta = \frac{\sin^{0}(4\theta)\sin^{3}(2\theta)}{\sin^{3}(2\theta) },
\gamma = \frac{\sin^{0}(8\theta)\sin^{3}(4\theta)}{\sin^{3}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_3}
x^3 + 4 x^2 - 11 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -1 $.
And
\begin{equation} \label{fmn_0_3}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1}
\end{equation}
\begin{equation} \label{gmn_0_3}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{8}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_0_6}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)\sin^{6}(8\theta)}{\sin^{6}(4\theta) },
\beta = \frac{\sin^{0}(4\theta)\sin^{6}(2\theta)}{\sin^{6}(2\theta) },
\gamma = \frac{\sin^{0}(8\theta)\sin^{6}(4\theta)}{\sin^{6}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_6}
x^3 - 38 x^2 + 129 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 27 $.
And
\begin{equation} \label{fmn_0_6}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{125}
\end{equation}
\begin{equation} \label{gmn_0_6}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{216}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_0_9}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)\sin^{9}(8\theta)}{\sin^{9}(4\theta) },
\beta = \frac{\sin^{0}(4\theta)\sin^{9}(2\theta)}{\sin^{9}(2\theta) },
\gamma = \frac{\sin^{0}(8\theta)\sin^{9}(4\theta)}{\sin^{9}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_9}
x^3 + 193 x^2 - 1460 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 41 $.
And
\begin{equation} \label{fmn_0_9}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{64}
\end{equation}
\begin{equation} \label{gmn_0_9}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1331}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_0_12}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)\sin^{12}(8\theta)}{\sin^{12}(4\theta) },
\beta = \frac{\sin^{0}(4\theta)\sin^{12}(2\theta)}{\sin^{12}(2\theta) },
\gamma = \frac{\sin^{0}(8\theta)\sin^{12}(4\theta)}{\sin^{12}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_12}
x^3 - 1186 x^2 + 16565 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 335 $.
And
\begin{equation} \label{fmn_0_12}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{2197}
\end{equation}
\begin{equation} \label{gmn_0_12}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{17576}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_0_15}
Let
$$
\alpha = \frac{\sin^{0}(2\theta)\sin^{15}(8\theta)}{\sin^{15}(4\theta) },
\beta = \frac{\sin^{0}(4\theta)\sin^{15}(2\theta)}{\sin^{15}(2\theta) },
\gamma = \frac{\sin^{0}(8\theta)\sin^{15}(4\theta)}{\sin^{15}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_0_15}
x^3 + 6829 x^2 - 187926 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 909 $.
And
\begin{equation} \label{fmn_0_15}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{4096}
\end{equation}
\begin{equation} \label{gmn_0_15}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{185193}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_1_2}
Let
$$
\alpha = \frac{\sin^{1}(2\theta)\sin^{1}(8\theta)}{\sin^{2}(4\theta) },
\beta = \frac{\sin^{1}(4\theta)\sin^{1}(2\theta)}{\sin^{2}(2\theta) },
\gamma = \frac{\sin^{1}(8\theta)\sin^{1}(4\theta)}{\sin^{2}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_1_2}
x^3 - 3 x^2 - 4 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_1_2}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{0}
\end{equation}
\begin{equation} \label{gmn_1_2}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{7}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_1_5}
Let
$$
\alpha = \frac{\sin^{1}(2\theta)\sin^{4}(8\theta)}{\sin^{5}(4\theta) },
\beta = \frac{\sin^{1}(4\theta)\sin^{4}(2\theta)}{\sin^{5}(2\theta) },
\gamma = \frac{\sin^{1}(8\theta)\sin^{4}(4\theta)}{\sin^{5}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_1_5}
x^3 + 25 x^2 + 31 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -10 $.
And
\begin{equation} \label{fmn_1_5}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_1_5}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{7}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_1_8}
Let
$$
\alpha = \frac{\sin^{1}(2\theta)\sin^{7}(8\theta)}{\sin^{8}(4\theta) },
\beta = \frac{\sin^{1}(4\theta)\sin^{7}(2\theta)}{\sin^{8}(2\theta) },
\gamma = \frac{\sin^{1}(8\theta)\sin^{7}(4\theta)}{\sin^{8}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_1_8}
x^3 - 136 x^2 - 361 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -31 $.
And
\begin{equation} \label{fmn_1_8}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_1_8}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{448}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_1_11}
Let
$$
\alpha = \frac{\sin^{1}(2\theta)\sin^{10}(8\theta)}{\sin^{11}(4\theta) },
\beta = \frac{\sin^{1}(4\theta)\sin^{10}(2\theta)}{\sin^{11}(2\theta) },
\gamma = \frac{\sin^{1}(8\theta)\sin^{10}(4\theta)}{\sin^{11}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_1_11}
x^3 + 816 x^2 + 4091 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -171 $.
And
\begin{equation} \label{fmn_1_11}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1323}
\end{equation}
\begin{equation} \label{gmn_1_11}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{3584}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_1_14}
Let
$$
\alpha = \frac{\sin^{1}(2\theta)\sin^{13}(8\theta)}{\sin^{14}(4\theta) },
\beta = \frac{\sin^{1}(4\theta)\sin^{13}(2\theta)}{\sin^{14}(2\theta) },
\gamma = \frac{\sin^{1}(8\theta)\sin^{13}(4\theta)}{\sin^{14}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_1_14}
x^3 - 4735 x^2 - 46414 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -535 $.
And
\begin{equation} \label{fmn_1_14}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{3136}
\end{equation}
\begin{equation} \label{gmn_1_14}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{48013}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_2_1}
Let
$$
\alpha = \frac{\sin^{2}(2\theta)}{\sin^{1}(4\theta) \sin^{1}(8\theta)},
\beta = \frac{\sin^{2}(4\theta)}{\sin^{1}(8\theta) \sin^{1}(2\theta)},
\gamma = \frac{\sin^{2}(8\theta)}{\sin^{1}(2\theta) \sin^{1}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_2_1}
x^3 + 4 x^2 + 3 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_2_1}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{7}
\end{equation}
\begin{equation} \label{gmn_2_1}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{0}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_2_4}
Let
$$
\alpha = \frac{\sin^{2}(2\theta)\sin^{2}(8\theta)}{\sin^{4}(4\theta) },
\beta = \frac{\sin^{2}(4\theta)\sin^{2}(2\theta)}{\sin^{4}(2\theta) },
\gamma = \frac{\sin^{2}(8\theta)\sin^{2}(4\theta)}{\sin^{4}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_2_4}
x^3 - 17 x^2 + 10 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 11 $.
And
\begin{equation} \label{fmn_2_4}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{56}
\end{equation}
\begin{equation} \label{gmn_2_4}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_2_7}
Let
$$
\alpha = \frac{\sin^{2}(2\theta)\sin^{5}(8\theta)}{\sin^{7}(4\theta) },
\beta = \frac{\sin^{2}(4\theta)\sin^{5}(2\theta)}{\sin^{7}(2\theta) },
\gamma = \frac{\sin^{2}(8\theta)\sin^{5}(4\theta)}{\sin^{7}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_2_7}
x^3 + 95 x^2 - 88 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 11 $.
And
\begin{equation} \label{fmn_2_7}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{56}
\end{equation}
\begin{equation} \label{gmn_2_7}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_2_10}
Let
$$
\alpha = \frac{\sin^{2}(2\theta)\sin^{8}(8\theta)}{\sin^{10}(4\theta) },
\beta = \frac{\sin^{2}(4\theta)\sin^{8}(2\theta)}{\sin^{10}(2\theta) },
\gamma = \frac{\sin^{2}(8\theta)\sin^{8}(4\theta)}{\sin^{10}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_2_10}
x^3 - 563 x^2 + 1011 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 102 $.
And
\begin{equation} \label{fmn_2_10}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{875}
\end{equation}
\begin{equation} \label{gmn_2_10}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{1323}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_2_13}
Let
$$
\alpha = \frac{\sin^{2}(2\theta)\sin^{11}(8\theta)}{\sin^{13}(4\theta) },
\beta = \frac{\sin^{2}(4\theta)\sin^{11}(2\theta)}{\sin^{13}(2\theta) },
\gamma = \frac{\sin^{2}(8\theta)\sin^{11}(4\theta)}{\sin^{13}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_2_13}
x^3 + 3280 x^2 - 11463 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 291 $.
And
\begin{equation} \label{fmn_2_13}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{2401}
\end{equation}
\begin{equation} \label{gmn_2_13}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{10584}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_0}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)}{\sin^{0}(4\theta) \sin^{3}(8\theta)},
\beta = \frac{\sin^{3}(4\theta)}{\sin^{0}(8\theta) \sin^{3}(2\theta)},
\gamma = \frac{\sin^{3}(8\theta)}{\sin^{0}(2\theta) \sin^{3}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_0}
x^3 + 4 x^2 - 11 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -1 $.
And
\begin{equation} \label{fmn_3_0}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1}
\end{equation}
\begin{equation} \label{gmn_3_0}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{8}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_3}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)}{\sin^{3}(4\theta) \sin^{0}(8\theta)},
\beta = \frac{\sin^{3}(4\theta)}{\sin^{3}(8\theta) \sin^{0}(2\theta)},
\gamma = \frac{\sin^{3}(8\theta)}{\sin^{3}(2\theta) \sin^{0}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_3}
x^3 + 11 x^2 - 4 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -1 $.
And
\begin{equation} \label{fmn_3_3}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{8}
\end{equation}
\begin{equation} \label{gmn_3_3}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_6}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)\sin^{3}(8\theta)}{\sin^{6}(4\theta) },
\beta = \frac{\sin^{3}(4\theta)\sin^{3}(2\theta)}{\sin^{6}(2\theta) },
\gamma = \frac{\sin^{3}(8\theta)\sin^{3}(4\theta)}{\sin^{6}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_6}
x^3 - 66 x^2 - 25 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -15 $.
And
\begin{equation} \label{fmn_3_6}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{27}
\end{equation}
\begin{equation} \label{gmn_3_6}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{64}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_9}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)\sin^{6}(8\theta)}{\sin^{9}(4\theta) },
\beta = \frac{\sin^{3}(4\theta)\sin^{6}(2\theta)}{\sin^{9}(2\theta) },
\gamma = \frac{\sin^{3}(8\theta)\sin^{6}(4\theta)}{\sin^{9}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_9}
x^3 + 389 x^2 + 248 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -43 $.
And
\begin{equation} \label{fmn_3_9}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{512}
\end{equation}
\begin{equation} \label{gmn_3_9}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{125}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_12}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)\sin^{9}(8\theta)}{\sin^{12}(4\theta) },
\beta = \frac{\sin^{3}(4\theta)\sin^{9}(2\theta)}{\sin^{12}(2\theta) },
\gamma = \frac{\sin^{3}(8\theta)\sin^{9}(4\theta)}{\sin^{12}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_12}
x^3 - 2271 x^2 - 2832 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -183 $.
And
\begin{equation} \label{fmn_3_12}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{1728}
\end{equation}
\begin{equation} \label{gmn_3_12}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{3375}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_3_15}
Let
$$
\alpha = \frac{\sin^{3}(2\theta)\sin^{12}(8\theta)}{\sin^{15}(4\theta) },
\beta = \frac{\sin^{3}(4\theta)\sin^{12}(2\theta)}{\sin^{15}(2\theta) },
\gamma = \frac{\sin^{3}(8\theta)\sin^{12}(4\theta)}{\sin^{15}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_3_15}
x^3 + 13297 x^2 + 32119 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -778 $.
And
\begin{equation} \label{fmn_3_15}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{15625}
\end{equation}
\begin{equation} \label{gmn_3_15}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{29791}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_4_2}
Let
$$
\alpha = \frac{\sin^{4}(2\theta)}{\sin^{2}(4\theta) \sin^{2}(8\theta)},
\beta = \frac{\sin^{4}(4\theta)}{\sin^{2}(8\theta) \sin^{2}(2\theta)},
\gamma = \frac{\sin^{4}(8\theta)}{\sin^{2}(2\theta) \sin^{2}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_4_2}
x^3 - 10 x^2 + 17 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 11 $.
And
\begin{equation} \label{fmn_4_2}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_4_2}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{56}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_4_5}
Let
$$
\alpha = \frac{\sin^{4}(2\theta)\sin^{1}(8\theta)}{\sin^{5}(4\theta) },
\beta = \frac{\sin^{4}(4\theta)\sin^{1}(2\theta)}{\sin^{5}(2\theta) },
\gamma = \frac{\sin^{4}(8\theta)\sin^{1}(4\theta)}{\sin^{5}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_4_5}
x^3 + 46 x^2 + 3 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_4_5}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_4_5}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{0}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_4_8}
Let
$$
\alpha = \frac{\sin^{4}(2\theta)\sin^{4}(8\theta)}{\sin^{8}(4\theta) },
\beta = \frac{\sin^{4}(4\theta)\sin^{4}(2\theta)}{\sin^{8}(2\theta) },
\gamma = \frac{\sin^{4}(8\theta)\sin^{4}(4\theta)}{\sin^{8}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_4_8}
x^3 - 269 x^2 + 66 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 39 $.
And
\begin{equation} \label{fmn_4_8}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{392}
\end{equation}
\begin{equation} \label{gmn_4_8}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{189}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_4_11}
Let
$$
\alpha = \frac{\sin^{4}(2\theta)\sin^{7}(8\theta)}{\sin^{11}(4\theta) },
\beta = \frac{\sin^{4}(4\theta)\sin^{7}(2\theta)}{\sin^{11}(2\theta) },
\gamma = \frac{\sin^{4}(8\theta)\sin^{7}(4\theta)}{\sin^{11}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_4_11}
x^3 + 1572 x^2 - 697 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 81 $.
And
\begin{equation} \label{fmn_4_11}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1323}
\end{equation}
\begin{equation} \label{gmn_4_11}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{448}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_4_14}
Let
$$
\alpha = \frac{\sin^{4}(2\theta)\sin^{10}(8\theta)}{\sin^{14}(4\theta) },
\beta = \frac{\sin^{4}(4\theta)\sin^{10}(2\theta)}{\sin^{14}(2\theta) },
\gamma = \frac{\sin^{4}(8\theta)\sin^{10}(4\theta)}{\sin^{14}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_4_14}
x^3 - 9201 x^2 + 7934 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 459 $.
And
\begin{equation} \label{fmn_4_14}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{10584}
\end{equation}
\begin{equation} \label{gmn_4_14}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{9317}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_1}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)}{\sin^{1}(4\theta) \sin^{4}(8\theta)},
\beta = \frac{\sin^{5}(4\theta)}{\sin^{1}(8\theta) \sin^{4}(2\theta)},
\gamma = \frac{\sin^{5}(8\theta)}{\sin^{1}(2\theta) \sin^{4}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_1}
x^3 - 3 x^2 - 46 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_5_1}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{0}
\end{equation}
\begin{equation} \label{gmn_5_1}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_4}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)}{\sin^{4}(4\theta) \sin^{1}(8\theta)},
\beta = \frac{\sin^{5}(4\theta)}{\sin^{4}(8\theta) \sin^{1}(2\theta)},
\gamma = \frac{\sin^{5}(8\theta)}{\sin^{4}(2\theta) \sin^{1}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_4}
x^3 - 31 x^2 - 25 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -10 $.
And
\begin{equation} \label{fmn_5_4}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{7}
\end{equation}
\begin{equation} \label{gmn_5_4}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_7}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)\sin^{2}(8\theta)}{\sin^{7}(4\theta) },
\beta = \frac{\sin^{5}(4\theta)\sin^{2}(2\theta)}{\sin^{7}(2\theta) },
\gamma = \frac{\sin^{5}(8\theta)\sin^{2}(4\theta)}{\sin^{7}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_7}
x^3 + 186 x^2 + 3 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_5_7}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{189}
\end{equation}
\begin{equation} \label{gmn_5_7}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{0}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_10}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)\sin^{5}(8\theta)}{\sin^{10}(4\theta) },
\beta = \frac{\sin^{5}(4\theta)\sin^{5}(2\theta)}{\sin^{10}(2\theta) },
\gamma = \frac{\sin^{5}(8\theta)\sin^{5}(4\theta)}{\sin^{10}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_10}
x^3 - 1088 x^2 - 179 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -73 $.
And
\begin{equation} \label{fmn_5_10}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{875}
\end{equation}
\begin{equation} \label{gmn_5_10}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{392}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_13}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)\sin^{8}(8\theta)}{\sin^{13}(4\theta) },
\beta = \frac{\sin^{5}(4\theta)\sin^{8}(2\theta)}{\sin^{13}(2\theta) },
\gamma = \frac{\sin^{5}(8\theta)\sin^{8}(4\theta)}{\sin^{13}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_13}
x^3 + 6367 x^2 + 1956 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -213 $.
And
\begin{equation} \label{fmn_5_13}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{7000}
\end{equation}
\begin{equation} \label{gmn_5_13}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{1323}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_5_16}
Let
$$
\alpha = \frac{\sin^{5}(2\theta)\sin^{11}(8\theta)}{\sin^{16}(4\theta) },
\beta = \frac{\sin^{5}(4\theta)\sin^{11}(2\theta)}{\sin^{16}(2\theta) },
\gamma = \frac{\sin^{5}(8\theta)\sin^{11}(4\theta)}{\sin^{16}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_5_16}
x^3 - 37250 x^2 - 22229 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -955 $.
And
\begin{equation} \label{fmn_5_16}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{34391}
\end{equation}
\begin{equation} \label{gmn_5_16}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{25088}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_0}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)}{\sin^{0}(4\theta) \sin^{6}(8\theta)},
\beta = \frac{\sin^{6}(4\theta)}{\sin^{0}(8\theta) \sin^{6}(2\theta)},
\gamma = \frac{\sin^{6}(8\theta)}{\sin^{0}(2\theta) \sin^{6}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_0}
x^3 - 38 x^2 + 129 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 27 $.
And
\begin{equation} \label{fmn_6_0}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{125}
\end{equation}
\begin{equation} \label{gmn_6_0}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{216}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_3}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)}{\sin^{3}(4\theta) \sin^{3}(8\theta)},
\beta = \frac{\sin^{6}(4\theta)}{\sin^{3}(8\theta) \sin^{3}(2\theta)},
\gamma = \frac{\sin^{6}(8\theta)}{\sin^{3}(2\theta) \sin^{3}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_3}
x^3 + 25 x^2 + 66 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -15 $.
And
\begin{equation} \label{fmn_6_3}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{64}
\end{equation}
\begin{equation} \label{gmn_6_3}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{27}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_6}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)}{\sin^{6}(4\theta) \sin^{0}(8\theta)},
\beta = \frac{\sin^{6}(4\theta)}{\sin^{6}(8\theta) \sin^{0}(2\theta)},
\gamma = \frac{\sin^{6}(8\theta)}{\sin^{6}(2\theta) \sin^{0}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_6}
x^3 - 129 x^2 + 38 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 27 $.
And
\begin{equation} \label{fmn_6_6}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{216}
\end{equation}
\begin{equation} \label{gmn_6_6}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{125}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_9}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)\sin^{3}(8\theta)}{\sin^{9}(4\theta) },
\beta = \frac{\sin^{6}(4\theta)\sin^{3}(2\theta)}{\sin^{9}(2\theta) },
\gamma = \frac{\sin^{6}(8\theta)\sin^{3}(4\theta)}{\sin^{9}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_9}
x^3 + 753 x^2 - 25 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 6 $.
And
\begin{equation} \label{fmn_6_9}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{729}
\end{equation}
\begin{equation} \label{gmn_6_9}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_12}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)\sin^{6}(8\theta)}{\sin^{12}(4\theta) },
\beta = \frac{\sin^{6}(4\theta)\sin^{6}(2\theta)}{\sin^{12}(2\theta) },
\gamma = \frac{\sin^{6}(8\theta)\sin^{6}(4\theta)}{\sin^{12}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_12}
x^3 - 4406 x^2 + 493 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 167 $.
And
\begin{equation} \label{fmn_6_12}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{4913}
\end{equation}
\begin{equation} \label{gmn_6_12}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{1000}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_6_15}
Let
$$
\alpha = \frac{\sin^{6}(2\theta)\sin^{9}(8\theta)}{\sin^{15}(4\theta) },
\beta = \frac{\sin^{6}(4\theta)\sin^{9}(2\theta)}{\sin^{15}(2\theta) },
\gamma = \frac{\sin^{6}(8\theta)\sin^{9}(4\theta)}{\sin^{15}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_6_15}
x^3 + 25778 x^2 - 5485 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 461 $.
And
\begin{equation} \label{fmn_6_15}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{24389}
\end{equation}
\begin{equation} \label{gmn_6_15}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{4096}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_7_2}
Let
$$
\alpha = \frac{\sin^{7}(2\theta)}{\sin^{2}(4\theta) \sin^{5}(8\theta)},
\beta = \frac{\sin^{7}(4\theta)}{\sin^{2}(8\theta) \sin^{5}(2\theta)},
\gamma = \frac{\sin^{7}(8\theta)}{\sin^{2}(2\theta) \sin^{5}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_7_2}
x^3 - 3 x^2 - 186 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -3 $.
And
\begin{equation} \label{fmn_7_2}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{0}
\end{equation}
\begin{equation} \label{gmn_7_2}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{189}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_7_5}
Let
$$
\alpha = \frac{\sin^{7}(2\theta)}{\sin^{5}(4\theta) \sin^{2}(8\theta)},
\beta = \frac{\sin^{7}(4\theta)}{\sin^{5}(8\theta) \sin^{2}(2\theta)},
\gamma = \frac{\sin^{7}(8\theta)}{\sin^{5}(2\theta) \sin^{2}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_7_5}
x^3 + 88 x^2 - 95 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 11 $.
And
\begin{equation} \label{fmn_7_5}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_7_5}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{56}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_7_8}
Let
$$
\alpha = \frac{\sin^{7}(2\theta)\sin^{1}(8\theta)}{\sin^{8}(4\theta) },
\beta = \frac{\sin^{7}(4\theta)\sin^{1}(2\theta)}{\sin^{8}(2\theta) },
\gamma = \frac{\sin^{7}(8\theta)\sin^{1}(4\theta)}{\sin^{8}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_7_8}
x^3 - 521 x^2 - 60 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -45 $.
And
\begin{equation} \label{fmn_7_8}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{392}
\end{equation}
\begin{equation} \label{gmn_7_8}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{189}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_7_11}
Let
$$
\alpha = \frac{\sin^{7}(2\theta)\sin^{4}(8\theta)}{\sin^{11}(4\theta) },
\beta = \frac{\sin^{7}(4\theta)\sin^{4}(2\theta)}{\sin^{11}(2\theta) },
\gamma = \frac{\sin^{7}(8\theta)\sin^{4}(4\theta)}{\sin^{11}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_7_11}
x^3 + 3049 x^2 + 94 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -31 $.
And
\begin{equation} \label{fmn_7_11}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{3136}
\end{equation}
\begin{equation} \label{gmn_7_11}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{7}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_7_14}
Let
$$
\alpha = \frac{\sin^{7}(2\theta)\sin^{7}(8\theta)}{\sin^{14}(4\theta) },
\beta = \frac{\sin^{7}(4\theta)\sin^{7}(2\theta)}{\sin^{14}(2\theta) },
\gamma = \frac{\sin^{7}(8\theta)\sin^{7}(4\theta)}{\sin^{14}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_7_14}
x^3 - 17839 x^2 - 1369 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -346 $.
And
\begin{equation} \label{fmn_7_14}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{16807}
\end{equation}
\begin{equation} \label{gmn_7_14}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{2401}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_1}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)}{\sin^{1}(4\theta) \sin^{7}(8\theta)},
\beta = \frac{\sin^{8}(4\theta)}{\sin^{1}(8\theta) \sin^{7}(2\theta)},
\gamma = \frac{\sin^{8}(8\theta)}{\sin^{1}(2\theta) \sin^{7}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_1}
x^3 + 60 x^2 + 521 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -45 $.
And
\begin{equation} \label{fmn_8_1}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{189}
\end{equation}
\begin{equation} \label{gmn_8_1}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{392}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_4}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)}{\sin^{4}(4\theta) \sin^{4}(8\theta)},
\beta = \frac{\sin^{8}(4\theta)}{\sin^{4}(8\theta) \sin^{4}(2\theta)},
\gamma = \frac{\sin^{8}(8\theta)}{\sin^{4}(2\theta) \sin^{4}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_4}
x^3 - 66 x^2 + 269 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 39 $.
And
\begin{equation} \label{fmn_8_4}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{189}
\end{equation}
\begin{equation} \label{gmn_8_4}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{392}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_7}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)}{\sin^{7}(4\theta) \sin^{1}(8\theta)},
\beta = \frac{\sin^{8}(4\theta)}{\sin^{7}(8\theta) \sin^{1}(2\theta)},
\gamma = \frac{\sin^{8}(8\theta)}{\sin^{7}(2\theta) \sin^{1}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_7}
x^3 + 361 x^2 + 136 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -31 $.
And
\begin{equation} \label{fmn_8_7}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{448}
\end{equation}
\begin{equation} \label{gmn_8_7}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_10}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)\sin^{2}(8\theta)}{\sin^{10}(4\theta) },
\beta = \frac{\sin^{8}(4\theta)\sin^{2}(2\theta)}{\sin^{10}(2\theta) },
\gamma = \frac{\sin^{8}(8\theta)\sin^{2}(4\theta)}{\sin^{10}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_10}
x^3 - 2110 x^2 + 101 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 95 $.
And
\begin{equation} \label{fmn_8_10}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{2401}
\end{equation}
\begin{equation} \label{gmn_8_10}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{392}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_13}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)\sin^{5}(8\theta)}{\sin^{13}(4\theta) },
\beta = \frac{\sin^{8}(4\theta)\sin^{5}(2\theta)}{\sin^{13}(2\theta) },
\gamma = \frac{\sin^{8}(8\theta)\sin^{5}(4\theta)}{\sin^{13}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_13}
x^3 + 12345 x^2 - 298 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 81 $.
And
\begin{equation} \label{fmn_8_13}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{12096}
\end{equation}
\begin{equation} \label{gmn_8_13}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_8_16}
Let
$$
\alpha = \frac{\sin^{8}(2\theta)\sin^{8}(8\theta)}{\sin^{16}(4\theta) },
\beta = \frac{\sin^{8}(4\theta)\sin^{8}(2\theta)}{\sin^{16}(2\theta) },
\gamma = \frac{\sin^{8}(8\theta)\sin^{8}(4\theta)}{\sin^{16}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_8_16}
x^3 - 72229 x^2 + 3818 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 767 $.
And
\begin{equation} \label{fmn_8_16}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{74536}
\end{equation}
\begin{equation} \label{gmn_8_16}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{6125}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_0}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)}{\sin^{0}(4\theta) \sin^{9}(8\theta)},
\beta = \frac{\sin^{9}(4\theta)}{\sin^{0}(8\theta) \sin^{9}(2\theta)},
\gamma = \frac{\sin^{9}(8\theta)}{\sin^{0}(2\theta) \sin^{9}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_0}
x^3 + 193 x^2 - 1460 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 41 $.
And
\begin{equation} \label{fmn_9_0}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{64}
\end{equation}
\begin{equation} \label{gmn_9_0}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1331}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_3}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)}{\sin^{3}(4\theta) \sin^{6}(8\theta)},
\beta = \frac{\sin^{9}(4\theta)}{\sin^{3}(8\theta) \sin^{6}(2\theta)},
\gamma = \frac{\sin^{9}(8\theta)}{\sin^{3}(2\theta) \sin^{6}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_3}
x^3 + 25 x^2 - 753 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 6 $.
And
\begin{equation} \label{fmn_9_3}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1}
\end{equation}
\begin{equation} \label{gmn_9_3}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{729}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_6}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)}{\sin^{6}(4\theta) \sin^{3}(8\theta)},
\beta = \frac{\sin^{9}(4\theta)}{\sin^{6}(8\theta) \sin^{3}(2\theta)},
\gamma = \frac{\sin^{9}(8\theta)}{\sin^{6}(2\theta) \sin^{3}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_6}
x^3 - 248 x^2 - 389 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -43 $.
And
\begin{equation} \label{fmn_9_6}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{125}
\end{equation}
\begin{equation} \label{gmn_9_6}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{512}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_9}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)}{\sin^{9}(4\theta) \sin^{0}(8\theta)},
\beta = \frac{\sin^{9}(4\theta)}{\sin^{9}(8\theta) \sin^{0}(2\theta)},
\gamma = \frac{\sin^{9}(8\theta)}{\sin^{9}(2\theta) \sin^{0}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_9}
x^3 + 1460 x^2 - 193 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 41 $.
And
\begin{equation} \label{fmn_9_9}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{1331}
\end{equation}
\begin{equation} \label{gmn_9_9}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{64}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_12}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)\sin^{3}(8\theta)}{\sin^{12}(4\theta) },
\beta = \frac{\sin^{9}(4\theta)\sin^{3}(2\theta)}{\sin^{12}(2\theta) },
\gamma = \frac{\sin^{9}(8\theta)\sin^{3}(4\theta)}{\sin^{12}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_12}
x^3 - 8543 x^2 - 186 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -183 $.
And
\begin{equation} \label{fmn_9_12}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{8000}
\end{equation}
\begin{equation} \label{gmn_9_12}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{729}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_9_15}
Let
$$
\alpha = \frac{\sin^{9}(2\theta)\sin^{6}(8\theta)}{\sin^{15}(4\theta) },
\beta = \frac{\sin^{9}(4\theta)\sin^{6}(2\theta)}{\sin^{15}(2\theta) },
\gamma = \frac{\sin^{9}(8\theta)\sin^{6}(4\theta)}{\sin^{15}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_9_15}
x^3 + 49984 x^2 + 885 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -225 $.
And
\begin{equation} \label{fmn_9_15}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{50653}
\end{equation}
\begin{equation} \label{gmn_9_15}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{216}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_2}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)}{\sin^{2}(4\theta) \sin^{8}(8\theta)},
\beta = \frac{\sin^{10}(4\theta)}{\sin^{2}(8\theta) \sin^{8}(2\theta)},
\gamma = \frac{\sin^{10}(8\theta)}{\sin^{2}(2\theta) \sin^{8}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_2}
x^3 - 101 x^2 + 2110 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 95 $.
And
\begin{equation} \label{fmn_10_2}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{392}
\end{equation}
\begin{equation} \label{gmn_10_2}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{2401}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_5}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)}{\sin^{5}(4\theta) \sin^{5}(8\theta)},
\beta = \frac{\sin^{10}(4\theta)}{\sin^{5}(8\theta) \sin^{5}(2\theta)},
\gamma = \frac{\sin^{10}(8\theta)}{\sin^{5}(2\theta) \sin^{5}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_5}
x^3 + 179 x^2 + 1088 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -73 $.
And
\begin{equation} \label{fmn_10_5}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{392}
\end{equation}
\begin{equation} \label{gmn_10_5}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{875}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_8}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)}{\sin^{8}(4\theta) \sin^{2}(8\theta)},
\beta = \frac{\sin^{10}(4\theta)}{\sin^{8}(8\theta) \sin^{2}(2\theta)},
\gamma = \frac{\sin^{10}(8\theta)}{\sin^{8}(2\theta) \sin^{2}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_8}
x^3 - 1011 x^2 + 563 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 102 $.
And
\begin{equation} \label{fmn_10_8}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{1323}
\end{equation}
\begin{equation} \label{gmn_10_8}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{875}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_11}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)\sin^{1}(8\theta)}{\sin^{11}(4\theta) },
\beta = \frac{\sin^{10}(4\theta)\sin^{1}(2\theta)}{\sin^{11}(2\theta) },
\gamma = \frac{\sin^{10}(8\theta)\sin^{1}(4\theta)}{\sin^{11}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_11}
x^3 + 5912 x^2 + 269 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -73 $.
And
\begin{equation} \label{fmn_10_11}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{6125}
\end{equation}
\begin{equation} \label{gmn_10_11}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{56}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_14}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)\sin^{4}(8\theta)}{\sin^{14}(4\theta) },
\beta = \frac{\sin^{10}(4\theta)\sin^{4}(2\theta)}{\sin^{14}(2\theta) },
\gamma = \frac{\sin^{10}(8\theta)\sin^{4}(4\theta)}{\sin^{14}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_14}
x^3 - 34590 x^2 + 381 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 375 $.
And
\begin{equation} \label{fmn_10_14}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{35721}
\end{equation}
\begin{equation} \label{gmn_10_14}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{1512}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_10_17}
Let
$$
\alpha = \frac{\sin^{10}(2\theta)\sin^{7}(8\theta)}{\sin^{17}(4\theta) },
\beta = \frac{\sin^{10}(4\theta)\sin^{7}(2\theta)}{\sin^{17}(2\theta) },
\gamma = \frac{\sin^{10}(8\theta)\sin^{7}(4\theta)}{\sin^{17}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_10_17}
x^3 + 202381 x^2 - 2552 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 557 $.
And
\begin{equation} \label{fmn_10_17}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{200704}
\end{equation}
\begin{equation} \label{gmn_10_17}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{875}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_1}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)}{\sin^{1}(4\theta) \sin^{10}(8\theta)},
\beta = \frac{\sin^{11}(4\theta)}{\sin^{1}(8\theta) \sin^{10}(2\theta)},
\gamma = \frac{\sin^{11}(8\theta)}{\sin^{1}(2\theta) \sin^{10}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_1}
x^3 - 269 x^2 - 5912 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -73 $.
And
\begin{equation} \label{fmn_11_1}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{56}
\end{equation}
\begin{equation} \label{gmn_11_1}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{6125}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_4}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)}{\sin^{4}(4\theta) \sin^{7}(8\theta)},
\beta = \frac{\sin^{11}(4\theta)}{\sin^{4}(8\theta) \sin^{7}(2\theta)},
\gamma = \frac{\sin^{11}(8\theta)}{\sin^{4}(2\theta) \sin^{7}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_4}
x^3 - 94 x^2 - 3049 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -31 $.
And
\begin{equation} \label{fmn_11_4}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{7}
\end{equation}
\begin{equation} \label{gmn_11_4}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{3136}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_7}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)}{\sin^{7}(4\theta) \sin^{4}(8\theta)},
\beta = \frac{\sin^{11}(4\theta)}{\sin^{7}(8\theta) \sin^{4}(2\theta)},
\gamma = \frac{\sin^{11}(8\theta)}{\sin^{7}(2\theta) \sin^{4}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_7}
x^3 + 697 x^2 - 1572 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 81 $.
And
\begin{equation} \label{fmn_11_7}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{448}
\end{equation}
\begin{equation} \label{gmn_11_7}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1323}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_10}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)}{\sin^{10}(4\theta) \sin^{1}(8\theta)},
\beta = \frac{\sin^{11}(4\theta)}{\sin^{10}(8\theta) \sin^{1}(2\theta)},
\gamma = \frac{\sin^{11}(8\theta)}{\sin^{10}(2\theta) \sin^{1}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_10}
x^3 - 4091 x^2 - 816 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -171 $.
And
\begin{equation} \label{fmn_11_10}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{3584}
\end{equation}
\begin{equation} \label{gmn_11_10}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{1323}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_13}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)\sin^{2}(8\theta)}{\sin^{13}(4\theta) },
\beta = \frac{\sin^{11}(4\theta)\sin^{2}(2\theta)}{\sin^{13}(2\theta) },
\gamma = \frac{\sin^{11}(8\theta)\sin^{2}(4\theta)}{\sin^{13}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_13}
x^3 + 23937 x^2 - 361 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 102 $.
And
\begin{equation} \label{fmn_11_13}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{23625}
\end{equation}
\begin{equation} \label{gmn_11_13}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{49}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_11_16}
Let
$$
\alpha = \frac{\sin^{11}(2\theta)\sin^{5}(8\theta)}{\sin^{16}(4\theta) },
\beta = \frac{\sin^{11}(4\theta)\sin^{5}(2\theta)}{\sin^{16}(2\theta) },
\gamma = \frac{\sin^{11}(8\theta)\sin^{5}(4\theta)}{\sin^{16}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_11_16}
x^3 - 140052 x^2 - 865 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -759 $.
And
\begin{equation} \label{fmn_11_16}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{137781}
\end{equation}
\begin{equation} \label{gmn_11_16}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{3136}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_0}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)}{\sin^{0}(4\theta) \sin^{12}(8\theta)},
\beta = \frac{\sin^{12}(4\theta)}{\sin^{0}(8\theta) \sin^{12}(2\theta)},
\gamma = \frac{\sin^{12}(8\theta)}{\sin^{0}(2\theta) \sin^{12}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_0}
x^3 - 1186 x^2 + 16565 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 335 $.
And
\begin{equation} \label{fmn_12_0}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{2197}
\end{equation}
\begin{equation} \label{gmn_12_0}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{17576}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_3}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)}{\sin^{3}(4\theta) \sin^{9}(8\theta)},
\beta = \frac{\sin^{12}(4\theta)}{\sin^{3}(8\theta) \sin^{9}(2\theta)},
\gamma = \frac{\sin^{12}(8\theta)}{\sin^{3}(2\theta) \sin^{9}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_3}
x^3 + 186 x^2 + 8543 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -183 $.
And
\begin{equation} \label{fmn_12_3}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{729}
\end{equation}
\begin{equation} \label{gmn_12_3}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{8000}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_6}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)}{\sin^{6}(4\theta) \sin^{6}(8\theta)},
\beta = \frac{\sin^{12}(4\theta)}{\sin^{6}(8\theta) \sin^{6}(2\theta)},
\gamma = \frac{\sin^{12}(8\theta)}{\sin^{6}(2\theta) \sin^{6}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_6}
x^3 - 493 x^2 + 4406 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 167 $.
And
\begin{equation} \label{fmn_12_6}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{1000}
\end{equation}
\begin{equation} \label{gmn_12_6}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{4913}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_9}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)}{\sin^{9}(4\theta) \sin^{3}(8\theta)},
\beta = \frac{\sin^{12}(4\theta)}{\sin^{9}(8\theta) \sin^{3}(2\theta)},
\gamma = \frac{\sin^{12}(8\theta)}{\sin^{9}(2\theta) \sin^{3}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_9}
x^3 + 2832 x^2 + 2271 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -183 $.
And
\begin{equation} \label{fmn_12_9}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{3375}
\end{equation}
\begin{equation} \label{gmn_12_9}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{1728}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_12}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)}{\sin^{12}(4\theta) \sin^{0}(8\theta)},
\beta = \frac{\sin^{12}(4\theta)}{\sin^{12}(8\theta) \sin^{0}(2\theta)},
\gamma = \frac{\sin^{12}(8\theta)}{\sin^{12}(2\theta) \sin^{0}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_12}
x^3 - 16565 x^2 + 1186 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 335 $.
And
\begin{equation} \label{fmn_12_12}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{17576}
\end{equation}
\begin{equation} \label{gmn_12_12}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{2197}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_12_15}
Let
$$
\alpha = \frac{\sin^{12}(2\theta)\sin^{3}(8\theta)}{\sin^{15}(4\theta) },
\beta = \frac{\sin^{12}(4\theta)\sin^{3}(2\theta)}{\sin^{15}(2\theta) },
\gamma = \frac{\sin^{12}(8\theta)\sin^{3}(4\theta)}{\sin^{15}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_12_15}
x^3 + 96919 x^2 + 444 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -141 $.
And
\begin{equation} \label{fmn_12_15}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{97336}
\end{equation}
\begin{equation} \label{gmn_12_15}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{27}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_2}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)}{\sin^{2}(4\theta) \sin^{11}(8\theta)},
\beta = \frac{\sin^{13}(4\theta)}{\sin^{2}(8\theta) \sin^{11}(2\theta)},
\gamma = \frac{\sin^{13}(8\theta)}{\sin^{2}(2\theta) \sin^{11}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_2}
x^3 + 361 x^2 - 23937 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 102 $.
And
\begin{equation} \label{fmn_13_2}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_13_2}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{23625}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_5}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)}{\sin^{5}(4\theta) \sin^{8}(8\theta)},
\beta = \frac{\sin^{13}(4\theta)}{\sin^{5}(8\theta) \sin^{8}(2\theta)},
\gamma = \frac{\sin^{13}(8\theta)}{\sin^{5}(2\theta) \sin^{8}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_5}
x^3 + 298 x^2 - 12345 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 81 $.
And
\begin{equation} \label{fmn_13_5}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{49}
\end{equation}
\begin{equation} \label{gmn_13_5}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{12096}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_8}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)}{\sin^{8}(4\theta) \sin^{5}(8\theta)},
\beta = \frac{\sin^{13}(4\theta)}{\sin^{8}(8\theta) \sin^{5}(2\theta)},
\gamma = \frac{\sin^{13}(8\theta)}{\sin^{8}(2\theta) \sin^{5}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_8}
x^3 - 1956 x^2 - 6367 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -213 $.
And
\begin{equation} \label{fmn_13_8}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{1323}
\end{equation}
\begin{equation} \label{gmn_13_8}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{7000}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_11}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)}{\sin^{11}(4\theta) \sin^{2}(8\theta)},
\beta = \frac{\sin^{13}(4\theta)}{\sin^{11}(8\theta) \sin^{2}(2\theta)},
\gamma = \frac{\sin^{13}(8\theta)}{\sin^{11}(2\theta) \sin^{2}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_11}
x^3 + 11463 x^2 - 3280 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 291 $.
And
\begin{equation} \label{fmn_13_11}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{10584}
\end{equation}
\begin{equation} \label{gmn_13_11}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{2401}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_14}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)\sin^{1}(8\theta)}{\sin^{14}(4\theta) },
\beta = \frac{\sin^{13}(4\theta)\sin^{1}(2\theta)}{\sin^{14}(2\theta) },
\gamma = \frac{\sin^{13}(8\theta)\sin^{1}(4\theta)}{\sin^{14}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_14}
x^3 - 67070 x^2 - 1733 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -619 $.
And
\begin{equation} \label{fmn_13_14}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{65219}
\end{equation}
\begin{equation} \label{gmn_13_14}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{3584}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_13_17}
Let
$$
\alpha = \frac{\sin^{13}(2\theta)\sin^{4}(8\theta)}{\sin^{17}(4\theta) },
\beta = \frac{\sin^{13}(4\theta)\sin^{4}(2\theta)}{\sin^{17}(2\theta) },
\gamma = \frac{\sin^{13}(8\theta)\sin^{4}(4\theta)}{\sin^{17}(8\theta) },
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_13_17}
x^3 + 392417 x^2 - 424 x - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 137 $.
And
\begin{equation} \label{fmn_13_17}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{392000}
\end{equation}
\begin{equation} \label{gmn_13_17}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
-\sqrt[3]{7}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_14_1}
Let
$$
\alpha = \frac{\sin^{14}(2\theta)}{\sin^{1}(4\theta) \sin^{13}(8\theta)},
\beta = \frac{\sin^{14}(4\theta)}{\sin^{1}(8\theta) \sin^{13}(2\theta)},
\gamma = \frac{\sin^{14}(8\theta)}{\sin^{1}(2\theta) \sin^{13}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_14_1}
x^3 + 1733 x^2 + 67070 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -619 $.
And
\begin{equation} \label{fmn_14_1}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{3584}
\end{equation}
\begin{equation} \label{gmn_14_1}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{65219}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_14_4}
Let
$$
\alpha = \frac{\sin^{14}(2\theta)}{\sin^{4}(4\theta) \sin^{10}(8\theta)},
\beta = \frac{\sin^{14}(4\theta)}{\sin^{4}(8\theta) \sin^{10}(2\theta)},
\gamma = \frac{\sin^{14}(8\theta)}{\sin^{4}(2\theta) \sin^{10}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_14_4}
x^3 - 381 x^2 + 34590 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 375 $.
And
\begin{equation} \label{fmn_14_4}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{1512}
\end{equation}
\begin{equation} \label{gmn_14_4}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{35721}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_14_7}
Let
$$
\alpha = \frac{\sin^{14}(2\theta)}{\sin^{7}(4\theta) \sin^{7}(8\theta)},
\beta = \frac{\sin^{14}(4\theta)}{\sin^{7}(8\theta) \sin^{7}(2\theta)},
\gamma = \frac{\sin^{14}(8\theta)}{\sin^{7}(2\theta) \sin^{7}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_14_7}
x^3 + 1369 x^2 + 17839 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -346 $.
And
\begin{equation} \label{fmn_14_7}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
-\sqrt[3]{2401}
\end{equation}
\begin{equation} \label{gmn_14_7}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{16807}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_14_10}
Let
$$
\alpha = \frac{\sin^{14}(2\theta)}{\sin^{10}(4\theta) \sin^{4}(8\theta)},
\beta = \frac{\sin^{14}(4\theta)}{\sin^{10}(8\theta) \sin^{4}(2\theta)},
\gamma = \frac{\sin^{14}(8\theta)}{\sin^{10}(2\theta) \sin^{4}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_14_10}
x^3 - 7934 x^2 + 9201 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ 459 $.
And
\begin{equation} \label{fmn_14_10}
\sqrt[3]{\alpha} + \sqrt[3]{\beta} + \sqrt[3]{\gamma} =
\sqrt[3]{9317}
\end{equation}
\begin{equation} \label{gmn_14_10}
\frac{1}{\sqrt[3]{\alpha}} + \frac{1}{\sqrt[3]{\beta}} + \frac{1}{\sqrt[3]{\gamma}} =
\sqrt[3]{10584}
\end{equation}
\end{theorem}
\begin{theorem} \label{tmn_14_13}
Let
$$
\alpha = \frac{\sin^{14}(2\theta)}{\sin^{13}(4\theta) \sin^{1}(8\theta)},
\beta = \frac{\sin^{14}(4\theta)}{\sin^{13}(8\theta) \sin^{1}(2\theta)},
\gamma = \frac{\sin^{14}(8\theta)}{\sin^{13}(2\theta) \sin^{1}(4\theta)},
$$
Then $ \{ \alpha, \beta, \gamma \} $ are roots of the equation:
\begin{equation} \label{emn_14_13}
x^3 + 46414 x^2 + 4735 x^2 - 1 = 0
\end{equation}
The associatd Rammnujan equation has integer solution $ -535 $.
And
\begin{equation} \label{fmn_1