import re
l=[["NBC","45","42"],["IBM","24","67"],["JIW","25"]]
#print l[0],l[1],l[2]
n=0
for n in range(3):
if re.match(l[n][0],"NBC").group():
print"1he"
#break or continue
elif re.match(l[n][0],"IBM").group():
print"2he"
#break
elif re.match(l[n][0],"JIW").group():
print"3he"
#break
else:print"no"
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