#include <bits/stdc++.h> 
 
using namespace std;  
 
typedef long long ll;  
typedef pair<ll, ll> ii;  
 
const int INF = 1e9;  
const ll LINF = 1e18;  
 
const int MOD = 998244353; 
const int N = 3e2 + 5; 
 
void add(int& a, int b) {
	a += b; 
	if (a >= MOD) a -= MOD; 
}
 
int n, m;   
ll a, b, c, d, e, f; 
map<ii, bool> obstacles; 
 
int dp[N][N][N]; // dp[i][n1][n2] = Số đường đi gồm i bước, trong đó đã đi n1 bước loại 1 và n2 bước loại 2
				 // Ta có n1 + n2 + n3 = i 
				 //  =>             n3 = i - n1 - n2
 
int main() {
	ios::sync_with_stdio(false); 
	cin.tie(nullptr); 	
	cin >> n >> m; 
	cin >> a >> b >> c >> d >> e >> f; 
 
	for (int i = 0; i < m; i++) {
		ll x, y; 
		cin >> x >> y; 
		obstacles[{x, y}] = true; 
	}
 
	dp[0][0][0] = 1;   
	for (int i = 1; i <= n; i++) {
		for (int n1 = 0; n1 <= i; n1++) {
			for (int n2 = 0; n1 + n2 <= i; n2++) {
				int n3 = i - n1 - n2;   
				// (x, y) chính là toạ độ hiện tại mà ta đang ở
				ll x = a * n1 + c * n2 + e * n3, y = b * n1 + d * n2 + f * n3;
				int& cur = dp[i][n1][n2]; 
				cur = 0; 
				if (obstacles.count({x, y})) continue;  
				// Bước thứ i 
				// Đi bước loại 1 
				if (n1 > 0) add(cur, dp[i - 1][n1 - 1][n2]);  
				// Đi bước loại 2
				if (n2 > 0) add(cur, dp[i - 1][n1][n2 - 1]); 
				// Đi bước loại 3
				if (n3 > 0) add(cur, dp[i - 1][n1][n2]);
			}
		}
	}
 
	int ans = 0;  
	for (int n1 = 0; n1 <= n; n1++) {
		for (int n2 = 0; n1 + n2 <= n; n2++) {
			add(ans, dp[n][n1][n2]); 
		}
	}
 
	cout << ans << '\n';
}

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

MiAyCjEgMSAxIDIgMSAzCjEgMgoyIDIK

2 2
1 1 1 2 1 3
1 2
2 2