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  1. #!/bin/bash
  2.  
  3. datestart="2013-06-01 00:00:00"
  4. dateend="2013-07-05 00:00:00"
  5.  
  6. date1="$datestart"
  7. while [[ "$date1" != "$dateend" ]]; do
  8.    date1="$(date -u --date="$date1 tomorrow" '+%Y-%m-%d %H:%M:%S')"
  9.    echo "$date1"
  10. done
Success #stdin #stdout 0.04s 5268KB
comments (?)
stdin 
Standard input is empty
stdout 
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https://ideone.com/3YQV9d
language:
Bash (bash 5.0.3)
created:
10 years ago
visibility:
public

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