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  1. import timeit
  2.  
  3.  
  4. def m1():
  5.     l1 = ['huita'] * 10000
  6.     for n in l1[::-1]:
  7.         pass
  8.  
  9. def m2():
  10.     l1 = ['huita'] * 10000
  11.     for n in reversed(l1):
  12.         pass
  13.  
  14. print(timeit.timeit(m1, number=10000))
  15. print(timeit.timeit(m2, number=10000))
Success #stdin #stdout 2.31s 9664KB
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1.3456066027283669
0.9445570334792137
https://ideone.com/g5MmEK
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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