import timeit


def m1():
    l1 = ['huita'] * 10000
    for n in l1[::-1]:
        pass

def m2():
    l1 = ['huita'] * 10000
    for n in reversed(l1):
        pass

print(timeit.timeit(m1, number=10000))
print(timeit.timeit(m2, number=10000))