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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	     int num = 12345;
  5.     int n = 3;
  6.     int log10 = (log(num)/log(10))+1;
  7.     int divisor = pow(10, log10-n);
  8.     int res = num / divisor;
  9.     printf("log10(num)+1=%d, divisor=%d, result=%d\n", log10, divisor, res);
  10. 	return 0;
  11. }
Success #stdin #stdout 0s 1832KB
comments (?)
stdin 
Standard input is empty
stdout 
log10(num)+1=5, divisor=100, result=123
https://ideone.com/XrQPWx
language:
C (gcc 8.3)
created:
12 years ago
visibility:
public

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