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  1. #include <stdio.h> // <stdio.h> contains a definition for `size_t`
  2.  
  3. // trying to find the minimum odd number in an array with just even numbers (or no numbers) is UB
  4. int oddmin(int *array, size_t length) {
  5.     size_t index = 0;
  6.     while (array[index] % 2 == 0) index++; /* skip even numbers */;
  7.     int minodd = array[index++]; // first odd number
  8.     while (index < length) {
  9.         if (array[index] % 2) {
  10.             if (array[index] < minodd) minodd = array[index];
  11.         }
  12.         index++;
  13.     }
  14.     return minodd;
  15. }
  16.  
  17. int main(void) {
  18.     int a[] = {1, 2, 3, -4, -5, -6, 7, 8, 9};
  19.     printf("odd minimum of array a is %d.\n", oddmin(a, 9));
  20.     int b[] = {1001};
  21.     printf("odd minimum of array b is %d.\n", oddmin(b, 1));
  22.     int c[] = {2, 2, 2, 2, 2, 2, 2, -3, 2, 2, 2, 2, 2, 2};
  23.     printf("odd minimum of array c is %d.\n", oddmin(c, sizeof c / sizeof *c));
  24.     int d[] = {2, 2, 2, 2, 2, 2, 2, -3, 2, 2, 2, -5, 2, 2};
  25.     printf("odd minimum of array d is %d.\n", oddmin(d, sizeof d / sizeof *d));
  26.     int e[] = {2, 2, 2, 2, 2, 2, 2, -5, 2, 2, 2, -3, 2, 2};
  27.     printf("odd minimum of array e is %d.\n", oddmin(e, sizeof e / sizeof *e));
  28.     int f[] = {42, 42, 42, 42};
  29.     printf("odd minimum of array f is **UB** (%d).\n", oddmin(f, sizeof f / sizeof *f));
  30.     int g[] = {3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3};
  31.     printf("odd minimum of array g is %d.\n", oddmin(g, sizeof g / sizeof *g));
  32. }
  33.  
Success #stdin #stdout 0s 9424KB
comments (?)
stdin 
Standard input is empty
stdout 
odd minimum of array a is -5.
odd minimum of array b is 1001.
odd minimum of array c is -3.
odd minimum of array d is -5.
odd minimum of array e is -5.
odd minimum of array f is **UB** (1).
odd minimum of array g is 3.
https://ideone.com/ReMpmO
min odd
language:
C (gcc 8.3)
created:
7 years ago
visibility:
secret

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