(defun f(a) (if (> a 9) (+ (mod a 10) (f(floor a 10))) (+ 0 a)))
(defun g(a) (and (= (mod (f a) 11) 0) (= (mod (f (+ a 7)) 11) 0)))
(loop for i from 100 to 999 do (if (g i) (print i)))
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