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  1. def last_digits(number, digit_count=3)
  2.   format_string = "%0#{digit_count}d"
  3.   return format_string % (number % 10**digit_count) 
  4. end
  5.  
  6. p [1, 12, 123, 1234].map { |e| last_digits(e) }
  7.  
  8.  
  9.  
Success #stdin #stdout 0.06s 9616KB
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Standard input is empty
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["001", "012", "123", "234"]
https://ideone.com/KGvkuV
language:
Ruby (ruby 2.5.5)
created:
10 years ago
visibility:
secret

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