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  1. def task(n):
  2. 	res=[]
  3. 	for i in range(1,(n//5+1)):
  4. 		if i*5 < n:
  5. 			j=n-i*5
  6. 			if j%3==0:
  7. 				res+=[(i,j//3)]
  8. 	return res
  9.  
  10. r=task(124)
  11. print(str(r))
  12.  
  13.  
Success #stdin #stdout 0.02s 9108KB
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Standard input is empty
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[(2, 38), (5, 33), (8, 28), (11, 23), (14, 18), (17, 13), (20, 8), (23, 3)]
https://ideone.com/ca8wOb
5*a+3*b
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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