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def task(n):
	res=[]
	for i in range(1,(n//5+1)):
		if i*5 < n:
			j=n-i*5
			if j%3==0:
				res+=[(i,j//3)]
	return res
 
r=task(124)
print(str(r))

Success #stdin #stdout 0.02s 9108KB

stdin

Standard input is empty

stdout

[(2, 38), (5, 33), (8, 28), (11, 23), (14, 18), (17, 13), (20, 8), (23, 3)]

https://ideone.com/ca8wOb

5*a+3*b

language:

Python 3 (python 3.12)

created:

visibility:

public

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