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  1. //Дана непустая строка S. Вывести строку, содержащую символы строки S, между которыми вставлено по 1 пробелу
  2. #include <iostream>
  3. #include <cstring>
  4. using namespace std;
  5. int main(){
  6. 	char S[] = "abcdefgh";
  7. 	char line[strlen(S)*2];
  8. 	memset(line, '*', strlen(S)*2 - 1);
  9. 	line[strlen(S)*2] = '\0';
  10. 	/*for(int i = 0; i < strlen(line); i++){
  11. 		if(i%2 == 0)
  12. 			line[i] = S[i/2];
  13. 	}*/
  14. 	for(int i = 0; i < strlen(S); i++){
  15. 			line[i*2] = S[i];
  16. 	}
  17. 	cout << line << endl;
  18. 	return 0;
  19. }
Success #stdin #stdout 0s 15232KB
comments (?)
stdin
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Standard input is empty
stdout
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a*b*c*d*e*f*g*h
https://ideone.com/zm6u1G
language:
C++14 (clang 8.0)
created:
5 years ago
visibility:
public

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