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  1. from itertools import groupby
  2.  
  3. lst = [('ask', 421), ('answer', 634), ('answer', 125), ('answer', 285), ('ask', 755), ('ask', 451), ('answer', 935), ('ask', 633)]
  4.  
  5. result = []
  6. for k, g in groupby(lst, lambda x: x[0]):
  7. 	i = -1 if k == 'ask' else 0
  8. 	result.append(list(g)[i])
  9.  
  10. print(result)
Success #stdin #stdout 0.02s 9048KB
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[('ask', 421), ('answer', 634), ('ask', 451), ('answer', 935), ('ask', 633)]
https://ideone.com/zeAEr2
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
secret

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