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  1. import re
  2. p = re.compile(r'\b([abcd])\s+([0-9]+(?:\.[0-9]+){3})(?:\(\d+\))? +-> +([0-9]+(?:\.[0-9]+){3})')
  3. test_str = "text textext text a 111.222.222.111(123) -> 22.222.111.111(7895)\ntxt txt txxt text b 22.111.22.222(8153) -> 153.33.233.111(195)\ntext text txt txt c 222.30.233.121 -> 44.233.111.111\ntxt text txt text d 22.111.22.222 -> 153.33.233.111"
  4. for x in test_str.split("\n"):
  5. 	print(re.findall(p, x))
Success #stdin #stdout 0.01s 9016KB
comments (?)
stdin 
Standard input is empty
stdout 
[('a', '111.222.222.111', '22.222.111.111')]
[('b', '22.111.22.222', '153.33.233.111')]
[('c', '222.30.233.121', '44.233.111.111')]
[('d', '22.111.22.222', '153.33.233.111')]
https://ideone.com/zXDxfD
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
secret

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