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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4.  
  5. 	int i,j,k;
  6. 	for(i=0;i<=100;i++){
  7. 		if(s[i]=='\0'){
  8. 		j=i-1;
  9.  
  10. 		}
  11. 	}
  12.  
  13. 	for(k=0;k<=j/2;k++){
  14. 		if(s[k]!=s[j-k]) return 0;
  15. 	}
  16. 	return 1;
  17.  
  18. 	//回文になっているとき１を返す
  19. 	//回文になっていないとき０を返す
  20. }
  21.  
  22. //メイン関数は書き換えなくてよいです
  23. int main(){
  24.     char s[100];
  25.     scanf("%s",s);
  26.     printf("%s -> %d\n",s,isPalindrome(s));
  27.     return 0;
  28. }
  29.  
Success #stdin #stdout 0s 5268KB
comments (?)
stdin
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araa
stdout
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araa -> 0
https://ideone.com/zRWmRD
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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