#include <stdio.h>
//a{n} = 2a{n-1} + a{n-2}, a{1}=2, a{2}=3(再帰なし版)
 
int main(void) {
    int n = 4;
    int a, b = 3, c = 2; 
    for(int i = 3; i <= n; i++){
        a = 2*b + c;
        a=b;
        b=c;
    }
	return 0;
}
 
 
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