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  1. %{
  2. #include <stdio.h>
  3. #include <string.h>
  4. // Define an array of C reserved words
  5. char *keywords[] = {
  6.     "auto", "break", "case", "char", "const", "continue", "default", "do", "double", "else", "enum", 
  7.     "extern", "float", "for", "goto", "if", "inline", "int", "long", "register", "restrict", "return", 
  8.     "short", "signed", "sizeof", "static", "struct", "switch", "typedef", "union", "unsigned", "void", 
  9.     "volatile", "while"
  10. };
  11. #define NUM_KEYWORDS 32
  12. // Function to check if a word is a keyword
  13. int is_keyword(char *word) {
  14.     for (int i = 0; i < NUM_KEYWORDS; i++) {
  15.         if (strcmp(word, keywords[i]) == 0) {
  16.             return 1; // It's a keyword
  17.         }
  18.     }
  19.     return 0; // It's not a keyword
  20. }
  21. %}
  22. %%
  23. [ \t\n]+                    ; // Ignore spaces, tabs, and newlines
  24. "int"|"float"|"char"|"void"|"long"|"short"|"double"|"return"|"if"|"else"|"for"|"while"|"do"|"break"|"continue" {
  25.     printf("Keyword: %s\n", yytext); // Print matched keywords
  26. }
  27. [A-Za-z_][A-Za-z0-9_]* {
  28.     if (is_keyword(yytext)) {
  29.         printf("Keyword: %s\n", yytext); // If it's a reserved word
  30.     } else {
  31.         printf("Identifier: %s\n", yytext); // If it's an identifier
  32.     }
  33. }
  34. . { ECHO; } // Print unmatched characters
  35. %%
  36. int main() {
  37.     printf("Enter C code:\n");
  38.     yylex(); // Start the lexical analysis
  39.     return 0;
  40. }
  41.  
Success #stdin #stdout #stderr 0.02s 6980KB
comments (?)
stdin 
Standard input is empty
stdout 
Standard output is empty
stderr 
ERROR: /home/seiqBx/prog:2:1: Syntax error: Operator expected
ERROR: /home/seiqBx/prog:40:1: Syntax error: Unexpected end of file
ERROR: '$runtoplevel'/0: Undefined procedure: program/0
   Exception: (3) program ? EOF: exit
https://ideone.com/ylN1cY
language:
Prolog (swi 7.6.4)
created:
9 days ago
visibility:
public

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