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  1. #include <stdio.h>
  2.  
  3. double a[500001]={0.0, 2.920050977316};
  4.  
  5. int main(void)
  6. {
  7.     int k, i;
  8.  
  9.     scanf("%d" ,&k);
  10.  
  11.     for(i=2; i<=k; i++)
  12.         a[i]=((int)a[i-1])*(a[i-1]-((int)a[i-1])+1.0);
  13.  
  14.     printf("%d" ,(int)a[k]);
  15.     return 0;
  16. }
Success #stdin #stdout 0s 19136KB
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https://ideone.com/y2pgAC
language:
C++ (gcc 8.3)
created:
5 years ago
visibility:
secret

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