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  1. import re
  2. s = "abc keyword1 ddd 111 ddd (ddd 99/ddd) 1 ddd (ddd) ddd 11 ddd keyword2 abc"
  3. m = re.search(r'keyword1(.*?)keyword2', s, re.I | re.S)
  4. if m:
  5.     print( re.sub(r'(\([^()]*\))|\s*\d+', r'\1', m.group(1)) )
  6.  
Success #stdin #stdout 0.03s 9536KB
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Standard input is empty
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 ddd ddd (ddd 99/ddd) ddd (ddd) ddd ddd
https://ideone.com/xPuJY2
language:
Python 3 (python  3.12)
created:
3 years ago
visibility:
secret

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