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  1. f = -> n, m {
  2.   (1...n).each_with_object(Hash.new {|h, k| h[k] = []}) {|b, acc|
  3.     (b + 1..n).each {|a|
  4.       c = a ** 3 - b ** 3
  5.       acc[c] << [a, b]
  6.       return acc[c] if acc[c].size == m
  7.     }
  8.   }.tap {break []}
  9. }
  10. p f.(10000, 5) # [[1134, 357], [1155, 504], [1246, 805], [2115, 2004], [4746, 4725]]
Time limit exceeded #stdin #stdout 5s 655256KB
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https://ideone.com/wBX9Rs
language:
Ruby (ruby 2.5.5)
created:
86 days ago
visibility:
secret

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