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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int x[30],n;
  5. 	x[1]=1;
  6. 	for(n=2;n<30;n++){
  7. 		x[n]=2*x[n-2]+1;
  8. 	}
  9. 	while(x[n]<1000){
  10. 		n++;
  11. 	}
  12. 	printf("%d",n);
  13. 	return 0;
  14. }
  15.  
Success #stdin #stdout 0s 5288KB
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35
https://ideone.com/w8zr4x
language:
C (gcc 8.3)
created:
45 days ago
visibility:
public

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