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  1. import itertools
  2.  
  3. def next_balanced_parens(s):
  4.     num_pairs = len(s)//2
  5.     depth = 0
  6.     for i in range(len(s)-1, -1, -1):
  7.         if s[i] == ")":
  8.             depth += 1
  9.         else:
  10.             assert s[i] == "("
  11.             depth -= 1
  12.             if depth > 0:
  13.                 break
  14.     else:
  15.         return "(" * (num_pairs+1) + ")" * (num_pairs+1)
  16.  
  17.     left = s[:i] + ")"
  18.     l = num_pairs - left.count("(")
  19.     r = num_pairs - left.count(")")
  20.     return left + "("*l + ")"*r
  21.  
  22. def iter_balanced_parens():
  23.     s = ""
  24.     while True:
  25.         yield s
  26.         s = next_balanced_parens(s)
  27.  
  28. last = None
  29. for s in itertools.islice(iter_balanced_parens(), 100):
  30.     if last is None or last < s or len(last) < len(s):
  31.         print(s)
  32.     else:
  33.         print(s, "lexicographic ordering error!")
  34.     last = s
Success #stdin #stdout 0.02s 9192KB
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https://ideone.com/vFNF59
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
public

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