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  1. #include <iostream>
  2. #include <cmath>
  3. using namespace std;
  4.  
  5. int main() {
  6. 	int b1, b2, b3, need, pas;
  7. 	cin >> b1 >> b2 >> b3;
  8. 	need = (b1 + b2 + b3) / 3;
  9. 	if ((b1 + b2 + b3) % 3!=0) {
  10. 		cout << "IMPOSSIBLE";
  11. 		return 0;
  12. 	}
  13. 	else cout << (abs(b1 - need) + abs(b2 - need) + abs(b3 - need))/2;
  14. 	return 0;
  15. }
Success #stdin #stdout 0s 15232KB
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stdin
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100 100 100
stdout
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Standard output is empty
https://ideone.com/uXm2Rf
language:
C++ (gcc 8.3)
created:
6 years ago
visibility:
secret

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