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  1. import re
  2. s= ''''abc'            (17245...64590)
  3. 'cde'            (12244...67730)
  4. 'dsa'            complement (12345...67890)'''
  5. for m in re.finditer(r'\s{2,}(?:(\w+)\s*)?\(([\d.]+)\)', s):
  6. 	res = []
  7. 	if m.group(1):
  8. 		res.append(m.group(1))
  9. 	res.extend(re.findall(r'\d+', m.group(2)))
  10. 	print(", ".join(res))
Success #stdin #stdout 0s 23304KB
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Standard input is empty
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17245, 64590
12244, 67730
complement, 12345, 67890
https://ideone.com/u0uGSp
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
public

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