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  1. class Solution:
  2.     def isAnagram(self, s: str, t: str) -> bool:
  3.         map1 = {}
  4.         map2 = {}
  5.         for char in s:
  6.             if char not in map1:
  7.                 map1[char] = 1
  8.             else :
  9.                 map1[char] += 1
  10.  
  11.         for char in t:
  12.             if char not in map2:
  13.                 map2[char] = 1
  14.             else :
  15.                 map2[char] += 1
  16.  
  17.         return map1 == map2
  18.  
Success #stdin #stdout 0.09s 14068KB
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https://ideone.com/t88FGp
language:
Python 3 (python  3.12)
created:
3 days ago
visibility:
public

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