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  1. #include <stdio.h>
  2. #include <string.h>
  3. #define AGE_PENSION 60
  4. #define AGE_MATURE 18
  5.  
  6. char* getAgeDescriptionByAge(int age)
  7. {
  8. 	if (age > 4 && age < 21)
  9. 		return " лет.\n";
  10.  
  11.     switch (age%10)
  12.     {
  13.     case 1:
  14.         return " год.\n";
  15.     case 2:
  16.     case 3:
  17.     case 4:
  18.         return " года.\n";
  19.     default:
  20.         return " лет.\n";
  21.     }
  22. }
  23.  
  24. void printAgeInfo(int age)
  25. {
  26.     char yourAgeString [64]  = "Ваш возраст %d ";
  27.     char youMatureString [64] = "Вы совершеннолетний %d ";
  28.     char ageUntilMatureString [64] = "Вам до совершеннолетия %d ";
  29.     char youOnPensionString [64] = "Вы на пенсии %d ";
  30.     char ageUntilPensionString [64] = "Вам до пенсии %d ";
  31.  
  32.     printf(strcat(yourAgeString, getAgeDescriptionByAge(age)), age);
  33.     if (age >= AGE_MATURE)
  34.         printf(strcat(youMatureString, getAgeDescriptionByAge(age-AGE_MATURE)), age-AGE_MATURE);
  35.     else
  36.         printf(strcat(ageUntilMatureString, getAgeDescriptionByAge(AGE_MATURE-age)), AGE_MATURE-age);
  37.     if (age >= AGE_PENSION)
  38.         printf(strcat(youOnPensionString, getAgeDescriptionByAge(age-AGE_PENSION)), age-AGE_PENSION);
  39.     else
  40.         printf(strcat(ageUntilPensionString, getAgeDescriptionByAge(AGE_PENSION-age)), AGE_PENSION-age);
  41. }
  42.  
  43. int main() {
  44.     // your code goes here
  45.     printf("ВВедите количество лет\n");
  46.     int age = 0;
  47.     scanf("%d", &age);
  48.  
  49.     if (age < 0)
  50.         printf("некорректный возраст");
  51.     printAgeInfo(age);
  52.     return 0;
  53. }
Success #stdin #stdout 0s 2172KB
comments (?)
stdin 
11
stdout 
ВВедите количество лет
Ваш возраст 11  лет.
Вам до совершеннолетия 7  лет.
Вам до пенсии 49  лет.
https://ideone.com/9xsMyq
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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