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  1. #include <string>
  2. #include <iostream>
  3. #include <regex>
  4. using namespace std;
  5.  
  6. int main() {
  7. 	std::regex r(R"(\b(?!\d*(\d)\d*\1)\d+\b)");
  8. 	char *str = "1234567890 987 787";
  9.  
  10. 	for (cregex_iterator it(str, str + strlen(str), r); it != cregex_iterator{}; it++)
  11.     {
  12.         cout << (*it).str() << endl;
  13.     }
  14. 	return 0;
  15. }
  16.  
Success #stdin #stdout 0s 4944KB
comments (?)
stdin 
Standard input is empty
stdout 
1234567890
987
https://ideone.com/8BTGic
language:
C++14 (gcc 8.3)
created:
4 years ago
visibility:
secret

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