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  1. def main():
  2.     arr = [9,8,7,6,5,4,3,2,-11]
  3.     print(arr)
  4.     n = len(arr)
  5.     i = 1
  6.     while i < n and arr[i] == arr[0]:
  7.         i +=1
  8.     if i < n:
  9.       if arr[i - 1] < arr[ i ]:
  10.             flag = True
  11.             for j in range(i , n - 1):
  12.                 if arr[j] > arr[j+1]:
  13.                     flag = False
  14.             if flag is True:
  15.                print("Vector crescator!")
  16.             else:
  17.                print("Vector neordonat!")
  18.  
  19.       elif arr[i - 1] > arr[ i ]:
  20.             flag = True
  21.             for j in range(i, n - 1):
  22.                 if arr[j] < arr[j+1]:
  23.                     flag = False
  24.             if flag is True:
  25.                 print("Vector descrescator!")
  26.             else:
  27.                 print("Vector neordonat!")
  28.     else:
  29.         print("Constant Vector!")
  30.  
  31. main()
Success #stdin #stdout 0.03s 9020KB
comments (?)
stdin 
Standard input is empty
stdout 
[9, 8, 7, 6, 5, 4, 3, 2, -11]
Vector descrescator!
https://ideone.com/7HM5qx
Check order vector
language:
Python 3 (python  3.9.5)
created:
3 years ago
visibility:
public

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