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  1. import re
  2. regex = r"\d(?=(\d{3}))"
  3. test_str = "123456789"
  4. matches = re.finditer(regex, test_str)
  5.  
  6. for match in matches:
  7.  print(match.group()+match.group(1));
  8.  
Success #stdin #stdout 0.02s 27792KB
comments (?)
stdin 
Standard input is empty
stdout 
1234
2345
3456
4567
5678
6789
https://ideone.com/3r6frg
language:
Python 3 (python  3.12)
created:
8 years ago
visibility:
public

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