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  1. #include <iostream>
  2. #include <cmath>
  3.  
  4. double babylonianSquareRoot(double n) {
  5.     if (n < 0) {
  6.         std::cerr << "Error: Cannot compute square root of a negative number." << std::endl;
  7.         return -1; // Return -1 for invalid input
  8.     }
  9.  
  10.     double x = n;       // Initial guess
  11.     double y = 1.0;     // Second guess
  12.     double e = 0.000001; // Tolerance for convergence
  13.  
  14.     while ((x - y) > e) {
  15.         x = (x + y) / 2.0; // Update x as the average of x and y
  16.         y = n / x;         // Update y as n divided by the new x
  17.     }
  18.  
  19.     return x; // Return the computed square root
  20. }
  21.  
  22. int main() {
  23.     double number;
  24.  
  25.     std::cout << "Enter a number to compute its square root: ";
  26.     std::cin >> number;
  27.  
  28.     double result = babylonianSquareRoot(number);
  29.  
  30.     if (result != -1) { // Check for valid result
  31.         std::cout << "The square root of " << number << " is approximately: " << result << std::endl;
  32.     }
  33.  
  34.     return 0;
  35. }
  36.  
Success #stdin #stdout 0.01s 5292KB
comments (?)
stdin 
5
stdout 
Enter a number to compute its square root: The square root of 5 is approximately: 2.23607
https://ideone.com/3kWoY7
Babylonian SQRT
language:
C++ (gcc 8.3)
created:
2 days ago
visibility:
secret

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