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  1. import re
  2. test_str = "%$##@P^&#!)00000R{]]]////O.......G\"\"\"\"\"R;;$#!*%&#*A/////847M"
  3. pattern = r'[^A-Z]+'
  4. print(re.sub(pattern, '', test_str))
Success #stdin #stdout 0.02s 27728KB
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PROGRAM
https://ideone.com/1r2io1
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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