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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3.  
  4. int main(int argc, char *args[]) {
  5.   // get parameters from stdin
  6.   float a, b, c;
  7.   scanf("%f %f %f", &a, &b, &c);
  8.   float d, e, f;
  9.   scanf("%f %f %f", &d, &e, &f);
  10.  
  11.   // variables for answer
  12.   float x, y;
  13.  
  14.   /** Explanation for solving problem
  15.    * =============
  16.    *  ax + by = c
  17.    *  dx + ey = f
  18.    * =============
  19.    * 1. multiplying LCM or just CM for removing x (or y)
  20.    * ===================
  21.    *  d(ax + by) = d(c)
  22.    *  a(dx + ey) = a(f)
  23.    * ===================
  24.    * 2. subtract with two equations
  25.    * =========================
  26.    *     adx + dby = cd
  27.    *   - adx + aey = af
  28.    *  -----------------------
  29.    *    (db - ae)y = cd - af
  30.    * =========================
  31.    * 3. get y
  32.    * ===============
  33.    *       cd - af
  34.    *  y = ---------
  35.    *       db - ae
  36.    * ===============
  37.    * 4. get x
  38.    * ==============
  39.    *  ax + by = c
  40.    * ==============
  41.    *       c - by
  42.    *  x = --------
  43.    *         a
  44.    * ==============
  45.    * 5. solved
  46.   */
  47.  
  48.   // error handling for dividing by zero
  49.   if (d * b == a * e) {
  50.     puts("-1");
  51.     return 1;
  52.   }
  53.   y = (d * c - a * f) / (d * b - a * e);
  54.  
  55.   // error handling for dividing by zero
  56.   if (a == 0) {
  57.     puts("-1");
  58.     return 1;
  59.   }
  60.   x = (c - b * y) / a;
  61.  
  62.   // print answer
  63.   printf("%.01f\n", x);
  64.   printf("%.01f\n", y);
  65.  
  66.   return 0;
  67. }
  68.  
Success #stdin #stdout 0s 4528KB
comments (?)
stdin 
1 1 2
2 -1 1
stdout 
1.0
1.0
https://ideone.com/1Pqo2a
language:
C (gcc 8.3)
created:
6 years ago
visibility:
public

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