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import re
p = re.compile(r'\b(?!914)\d{3}\b')
test_str = "123\n235\n456\n1000\n910 911 912 913\n  914\n915 916"
print(re.findall(p, test_str))

Success #stdin #stdout 0.01s 8968KB

stdin

Standard input is empty

stdout

['123', '235', '456', '910', '911', '912', '913', '915', '916']

https://ideone.com/0yhWuk

language:

Python (cpython 2.7.16)

created:

visibility:

secret

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