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  1. import re
  2. pattern = r"\b(?P<subsection>\d+(?:\s+\d\w*)+)\s+(?P<name>.*?)\s+(?P<date>\d{1,2}/\d{1,2}/\d{2})\b"
  3. text = "26 24 16  Panelboards  10/05/18 26 26 00i  Power Distribution Units – Install  10/05/18"
  4. print([x.groupdict() for x in re.finditer(pattern, text)])
  5.  
Success #stdin #stdout 0.03s 9644KB
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stdin 
Standard input is empty
stdout 
[{'subsection': '26 24 16', 'name': 'Panelboards', 'date': '10/05/18'}, {'subsection': '26 26 00i', 'name': 'Power Distribution Units – Install', 'date': '10/05/18'}]
https://ideone.com/zErfEC
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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