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  1. from math import sqrt
  2.  
  3. def issumofsqcube(n, count=0, b=2):
  4.     while (count <= 5 or b in range(2, 1 + int(pow(n - 4, 1/3)))):
  5.         if isinstance(sqrt(n - pow(b, 3)), int):
  6.             count = count + 1
  7.             b = b + 1
  8.         else:
  9.             return count
  10.  
  11. print(issumofsqcube(5229225))
  12.  
  13.  
Success #stdin #stdout 0.02s 8736KB
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https://ideone.com/yHQp8N
language:
Python 3 (python  3.9.5)
created:
9 years ago
visibility:
public

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