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  1. #include<stdio.h>
  2. #include<stdlib.h>
  3. long long int n,m,t,d,total=0,dra=0,tmp=0,i,j,bad[999999]={0},bl[999999]={0},x=1;
  4. int main () {
  5.     scanf("%lld%lld%lld",&n,&t,&m);
  6.     for(i=1;i<=m;i++){
  7.     scanf("%lld",&tmp);
  8.     bad[tmp]=1;
  9.     }
  10.     for(j=1;j<=t;j++){
  11.     for(i=1;i<=n;i++){
  12.        if(bad[i]==1){
  13.           bl[x]=i;
  14.           x++;
  15.        }
  16.     }
  17.     for(i=1;i<x;i++){
  18.        bad[bl[i]+1]=1;
  19.        bad[bl[i]-1]=1;
  20.        bl[x]=0;
  21.     }
  22.     for(i=1;i<=n;i++){
  23.        if(bad[i]==1){
  24.           total++;
  25.        }
  26.        }
  27.     printf("%lld\n",total);
  28.     total=0;
  29.     x=0;
  30.     }
  31.     return 0;
  32. }
  33.  
  34.  
Success #stdin #stdout 0.01s 18352KB
comments (?)
stdin 
10 2 3
2
3
10
stdout 
6
8
https://ideone.com/xHIKW
language:
C++ (gcc 8.3)
created:
14 years ago
visibility:
public

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