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  1. #include <stdio.h>
  2. //a{n+1} = -2a{n} + 4, a{0}=2(再帰なし版)
  3. int main(void) {
  4.     int n = 4;
  5.     int an= 2;
  6.     for(int i=0;i>n;i++){
  7.     	an=-2*(n-1)+4;
  8.     }
  9.  
  10.     printf("数列a%dの値は%d\n", n, an);
  11.  
  12. 	return 0;
  13. }
  14.  
  15.  
Success #stdin #stdout 0s 5288KB
comments (?)
stdin 
Standard input is empty
stdout 
数列a4の値は2
https://ideone.com/tEujlA
language:
C (gcc 8.3)
created:
72 days ago
visibility:
public

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