import re
 
def re_rsplit(pattern, text, maxsplit):
    if maxsplit == 0 or not pattern.search(text): # If split is 0 or less, or upon no match
        return [text]                            # Return the string itself as a one-item list
    prev = len(text)                             # Previous match value start position
    cnt = 0                                      # A match counter
    result = []                                  # Output list
    for m in reversed(list(pattern.finditer(text))):
        result.append(text[m.end():prev])        # Append a match to resulting list
        prev = m.start()                         # Set previous match start position
        cnt += 1                                 # Increment counter
        if maxsplit > 0 and cnt >= maxsplit:     # Break out of for loop if maxsplit is greater than 0 and...
            break                                # ...match count is more or equals max split value
    result.append(text[:prev])                   # Append the text chunk from start
    return reversed(result)                      # Return reversed list
 
splitme = "a!b?c!d"
pattern = re.compile(r'[!?]')
print(list(re_rsplit(pattern, splitme, -1))) # => ['a', 'b', 'c', 'd']
print(list(re_rsplit(pattern, splitme, 0)))  # => ['a!b?c!d']
print(list(re_rsplit(pattern, splitme, 1)))  # => ['a!b?c', 'd']
print(list(re_rsplit(pattern, splitme, 2)))  # => ['a!b', 'c', 'd']
print(list(re_rsplit(pattern, splitme, 3)))  # => ['a', 'b', 'c', 'd']
print(list(re_rsplit(pattern, splitme, 50))) # => ['a', 'b', 'c', 'd']

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