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  1. /* Program to print a given number in words. The program handles
  2.    numbers from 0 to 9999 */
  3. #include <stdio.h>
  4. #include <string.h>
  5. #include <stdlib.h>
  6. #include <iostream>
  7.  
  8. using namespace std;
  9.  
  10. /* A function that prints given number in words */
  11. void convert_to_words(char *num)
  12. {
  13.     int len = strlen(num);  // Get number of digits in given number
  14.  
  15.     /* Base cases */
  16.     if (len == 0) {
  17.         fprintf(stderr, "empty string\n");
  18.         return;
  19.     }
  20.     if (len > 4) {
  21.         fprintf(stderr, "Length more than 4 is not supported\n");
  22.         return;
  23.     }
  24.  
  25.     /* The first string is not used, it is to make array indexing simple */
  26.     string single_digits[] = { "zero", "one", "two", "three", "four",
  27.                               "five", "six", "seven", "eight", "nine"};
  28.  
  29.     /* The first string is not used, it is to make array indexing simple */
  30.     string two_digits[] = {"", "ten", "eleven", "twelve", "thirteen", "fourteen",
  31.                      "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
  32.  
  33.     /* The first two string are not used, they are to make array indexing simple*/
  34.     string tens_multiple[] = {"", "", "twenty", "thirty", "forty", "fifty",
  35.                              "sixty", "seventy", "eighty", "ninety"};
  36.  
  37.     string tens_power[] = {"hundred", "thousand"};
  38.  
  39.     /* Used for debugging purpose only */
  40.     printf("\n%s: ", num);
  41.  
  42.     /* For single digit number */
  43.     if (len == 1) {
  44.         cout << single_digits[*num - '0'] << " ";
  45.         return;
  46.     }
  47.  
  48.      /* Iterate while num is not '\0' */
  49.      while (*num != '\0') {
  50.  
  51.         /* Code path for first 2 digits */
  52.         if (len >= 3) {
  53.             if (*num -'0' != 0) {
  54.                 cout << single_digits[*num - '0'] << " ";
  55.                 cout << tens_power[len-3] << " "; // here len can be 3 or 4
  56.             }
  57.             --len;
  58.         }
  59.  
  60.         /* Code path for last 2 digits */
  61.         else {
  62.             /* Need to explicitly handle 10-19. Sum of the two digits is
  63.                used as index of "two_digits" array of strings */
  64.             if (*num == '1') {
  65.                 int sum = *num - '0' + *(num + 1)- '0';
  66.                 cout << two_digits[sum] << " ";
  67.                 return;
  68.             }
  69.  
  70.             /* Need to explicitely handle 20 */
  71.             else if (*num == '2' && *(num + 1) == '0') {
  72.                 cout << "twenty ";
  73.                 return;
  74.             }
  75.  
  76.             /* Rest of the two digit numbers i.e., 21 to 99 */
  77.             else {
  78.                 int i = *num - '0';
  79.                 cout << (i? tens_multiple[i]: "") << " ";
  80.                 ++num;
  81.                 if (*num != '0')
  82.                     cout << single_digits[*num - '0'] << " ";
  83.             }
  84.         }
  85.         ++num;
  86.     }
  87. }
  88.  
  89. /* Driver program to test above function */
  90. int main(void)
  91. {
  92.     cout << "Enter a number to convert to words:- ";
  93.  
  94.     char num[10];
  95.  
  96.     cin >> num;
  97.     convert_to_words(num);
  98.  
  99.     cout << endl;
  100.  
  101.     return 0;
  102. }
Success #stdin #stdout 0s 3468KB
comments (?)
stdin 
345
stdout 
Enter a number to convert to words:- 
345: three hundred forty five
https://ideone.com/p6aUvz
language:
C++ (gcc 8.3)
created:
8 years ago
visibility:
public

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