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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int n,i,sum=0;
  5.  
  6. 	printf("10000以下の完全数は、");
  7. 	for(n=1; n<=10000; n++){
  8. 		for(i=1;i<n;i++){
  9. 			if(n%i==0){
  10. 				sum = sum + i;
  11. 				};
  12. 			}
  13. 		if(n==sum){
  14. 			printf("%d ",n);
  15. 		}
  16. 		sum = 0;
  17. 	}
  18.  
  19. 	return 0;
  20. }
  21.  
Success #stdin #stdout 0.14s 5316KB
comments (?)
stdin 
6
stdout 
10000以下の完全数は、6 28 496 8128
https://ideone.com/lxyu9v
2026/5/14 提出課題1
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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