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  1. #include <stdio.h>
  2. //a{n} = -6a{n-1} -9a{n-2}, a{1}=1, a{2}=2(再帰あり版)
  3. int main(void){
  4. 	int i,n=4,a,b=3,c=2;
  5. 	for (i=3; i<=4; i++){
  6. 		a=2*b+c;
  7. 		c=b;
  8. 		b=a;
  9. 	}
  10. 	printf("%d no %d",n,a);
  11. }
  12.  
Success #stdin #stdout 0s 5280KB
comments (?)
stdin 
5
stdout 
4 no 19
https://ideone.com/hI2cmA
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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